Integrated Concepts A basketball player jumps straight up for a ball. To do this, he lowers his body 0.300 m and then accelerates through this…

  

Please help! 46.Integrated Concepts(a)(b)(c)47.Integrated Concepts(a)(b)(c)49.Integrated Concepts(a)(b)(c) (d) A basketball player jumps straight up for a ball. To do this, he lowers his body 0.300 m and then accelerates through this distance by forcefully straightening his legs. This player leaves the floor with a vertical velocity sufficient to carry him 0.900 m above the floor.   Calculate his velocity when he leaves the floor.   Calculate his acceleration while he is straightening his legs. He goes from zero to the velocity found in part (a) in a distance of 0.300 m.   Calculate the force he exerts on the floor to do this, given that his mass is 110 kg.  A 2.50-kg fireworks shell is fired straight up from a mortar and reaches a height of 110m.   Neglecting air resistance (a poor assumption, but we will make it for this example), calculate the shell’s velocity when it leaves the mortar.   The mortar itself is a tube 0.450 m long. Calculate the average acceleration of the shell in the tube as it goes from zero to the velocity found in (a).   What is the average force on the shell in the mortar? Express your answer in newtons and as a ratio to the weight of the shell.  An elevator filled with passengers has a mass of 1700 kg.   The elevator accelerates upward from rest at a rate of  1.20 m/s2  for 1.50 s. Calculate the tension in the cable supporting the elevator.   The elevator continues upward at constant velocity for 8.50 s. What is the tension in the cable during this time?  The elevator decelerates at a rate of  0.600 m/s2  for 3.00 s. What is the tension in the cable during deceleration?   How high has the elevator moved above its original starting point, and what is its final velocity?  Science Physics PHYSICS 114

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